LeanMachineLearning exposition

Learning.IT.adapted_hist🔗

This page has the declaration's own card below, then its dependency graph, then a card for each dependency (type dependencies first, then the rest of the transitive closure). For a theorem, the graph and the dependency cards only follow its statement's dependencies (its proof is replaced by sorry, so what it proves doesn't depend on how); for everything else, both the type and the body/value are followed, since their content is part of what later declarations build on.

Minimal Lean file

adapted_hist🔗

LemmaLearning.IT.adapted_hist

No docstring.

🔗theorem
Learning.IT.adapted_hist.{u_1, u_2} {𝓐 : Type u_1} {𝓨 : Type u_2} {m𝓐 : MeasurableSpace 𝓐} {m𝓨 : MeasurableSpace 𝓨} : MeasureTheory.Adapted (IT.filtration 𝓐 𝓨) hist
Learning.IT.adapted_hist.{u_1, u_2} {𝓐 : Type u_1} {𝓨 : Type u_2} {m𝓐 : MeasurableSpace 𝓐} {m𝓨 : MeasurableSpace 𝓨} : MeasureTheory.Adapted (IT.filtration 𝓐 𝓨) hist

Code

lemma adapted_hist : Adapted (IT.filtration 𝓐 𝓨) hist
Type uses (2)
Body uses (1)

Actions: Source · Open Issue

Proof
by
  intro n
  simp [filtration_eq_comap, measurable_iff_comap_le]

Dependency graph

Type dependencies (2)

filtration🔗

DefinitionLearning.IT.filtration

Filtration of the algorithm Seq.

🔗def
Learning.IT.filtration.{u_4, u_5} (𝓐 : Type u_4) (𝓨 : Type u_5) [MeasurableSpace 𝓐] [MeasurableSpace 𝓨] : MeasureTheory.Filtration inferInstance
Learning.IT.filtration.{u_4, u_5} (𝓐 : Type u_4) (𝓨 : Type u_5) [MeasurableSpace 𝓐] [MeasurableSpace 𝓨] : MeasureTheory.Filtration inferInstance

Code

protected def filtration (𝓐 𝓨 : Type*) [MeasurableSpace 𝓐] [MeasurableSpace 𝓨] :
    Filtration ℕ (inferInstance : MeasurableSpace (ℕ → 𝓐 × 𝓨)) :=
  MeasureTheory.Filtration.piLE (X := fun _ ↦ 𝓐 × 𝓨)
Used by (13)

Actions: Source · Open Issue

hist🔗

DefinitionLearning.IT.hist

hist n is the history up to time n. This is a random variable on the measurable space ℕ → 𝓐 × 𝓨.

🔗def
Learning.IT.hist.{u_1, u_2} {𝓐 : Type u_1} {𝓨 : Type u_2} (n : ) (h : 𝓐 × 𝓨) : (Finset.Iic n) 𝓐 × 𝓨
Learning.IT.hist.{u_1, u_2} {𝓐 : Type u_1} {𝓨 : Type u_2} (n : ) (h : 𝓐 × 𝓨) : (Finset.Iic n) 𝓐 × 𝓨

Code

def hist (n : ℕ) (h : ℕ → 𝓐 × 𝓨) : Iic n → 𝓐 × 𝓨 := fun i ↦ h i
Used by (23)

Actions: Source · Open Issue