Learning.stepsUntil_zero_of_ne
This page has the declaration's own card below, then its dependency graph, then a card for each dependency (type dependencies first, then the rest of the transitive closure). For a theorem, the graph and the dependency cards only follow its statement's dependencies (its proof is replaced by sorry, so what it proves doesn't depend on how); for everything else, both the type and the body/value are followed, since their content is part of what later declarations build on.
stepsUntil_zero_of_ne🔗
Learning.stepsUntil_zero_of_neNo docstring.
Learning.stepsUntil_zero_of_ne.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] {A : ℕ → Ω → 𝓐} {a : 𝓐} {ω : Ω} (hka : A 0 ω ≠ a) : stepsUntil A a 0 ω = 0Learning.stepsUntil_zero_of_ne.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] {A : ℕ → Ω → 𝓐} {a : 𝓐} {ω : Ω} (hka : A 0 ω ≠ a) : stepsUntil A a 0 ω = 0
Code
lemma stepsUntil_zero_of_ne (hka : A 0 ω ≠ a) : stepsUntil A a 0 ω = 0
Type uses (1)
Body uses (3)
Actions: Source · Open Issue
Proof
by unfold stepsUntil simp_rw [← bot_eq_zero, sInf_eq_bot, bot_eq_zero] intro n hn refine ⟨0, ?_, hn⟩ simp only [Set.mem_image, Set.mem_setOf_eq, Nat.cast_eq_zero, exists_eq_right, zero_add] rw [← zero_add 1, pullCount_eq_pullCount_of_action_ne hka] simp
Dependency graph
Type dependencies (1)
stepsUntil🔗
Learning.stepsUntil
Number of steps until action a was pulled exactly m times.
Learning.stepsUntil.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (m : ℕ) (ω : Ω) : ℕ∞Learning.stepsUntil.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (m : ℕ) (ω : Ω) : ℕ∞
Code
noncomputable
def stepsUntil (A : ℕ → Ω → 𝓐) (a : 𝓐) (m : ℕ) (ω : Ω) : ℕ∞ :=
sInf ((↑) '' {s | pullCount A a (s + 1) ω = m})Body uses (1)
Used by (46)
Actions: Source · Open Issue
All dependencies, transitively (1)
pullCount🔗
Learning.pullCount
Number of times action a was chosen up to time t (excluding t).
Learning.pullCount.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (t : ℕ) (ω : Ω) : ℕLearning.pullCount.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (t : ℕ) (ω : Ω) : ℕ
Code
noncomputable def pullCount (A : ℕ → Ω → 𝓐) (a : 𝓐) (t : ℕ) (ω : Ω) : ℕ := #(filter (fun s ↦ A s ω = a) (range t))
Actions: Source · Open Issue