Learning.stepsUntil_pullCount_le
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stepsUntil_pullCount_le🔗
Learning.stepsUntil_pullCount_leNo docstring.
Learning.stepsUntil_pullCount_le.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] {A : ℕ → Ω → 𝓐} (ω : Ω) (a : 𝓐) (t : ℕ) : stepsUntil A a (pullCount A a (t + 1) ω) ω ≤ ↑tLearning.stepsUntil_pullCount_le.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] {A : ℕ → Ω → 𝓐} (ω : Ω) (a : 𝓐) (t : ℕ) : stepsUntil A a (pullCount A a (t + 1) ω) ω ≤ ↑t
Code
lemma stepsUntil_pullCount_le (ω : Ω) (a : 𝓐) (t : ℕ) :
stepsUntil A a (pullCount A a (t + 1) ω) ω ≤ tType uses (2)
Used by (2)
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Proof
by rw [stepsUntil] exact csInf_le (OrderBot.bddBelow _) ⟨t, rfl, rfl⟩
Dependency graph
Type dependencies (2)
stepsUntil🔗
Learning.stepsUntil
Number of steps until action a was pulled exactly m times.
Learning.stepsUntil.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (m : ℕ) (ω : Ω) : ℕ∞Learning.stepsUntil.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (m : ℕ) (ω : Ω) : ℕ∞
Code
noncomputable
def stepsUntil (A : ℕ → Ω → 𝓐) (a : 𝓐) (m : ℕ) (ω : Ω) : ℕ∞ :=
sInf ((↑) '' {s | pullCount A a (s + 1) ω = m})Body uses (1)
Used by (46)
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pullCount🔗
Learning.pullCount
Number of times action a was chosen up to time t (excluding t).
Learning.pullCount.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (t : ℕ) (ω : Ω) : ℕLearning.pullCount.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (t : ℕ) (ω : Ω) : ℕ
Code
noncomputable def pullCount (A : ℕ → Ω → 𝓐) (a : 𝓐) (t : ℕ) (ω : Ω) : ℕ := #(filter (fun s ↦ A s ω = a) (range t))
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