Learning.stepsUntil_one_of_eq
If we pull action a at time 0, the first time at which it is pulled once is 0.
Learning.stepsUntil_one_of_eq.{u_1, u_3} {๐ : Type u_1} {ฮฉ : Type u_3} [DecidableEq ๐] {A : โ โ ฮฉ โ ๐} {a : ๐} {ฯ : ฮฉ} (hka : A 0 ฯ = a) : stepsUntil A a 1 ฯ = 0Learning.stepsUntil_one_of_eq.{u_1, u_3} {๐ : Type u_1} {ฮฉ : Type u_3} [DecidableEq ๐] {A : โ โ ฮฉ โ ๐} {a : ๐} {ฯ : ฮฉ} (hka : A 0 ฯ = a) : stepsUntil A a 1 ฯ = 0
Code
lemma stepsUntil_one_of_eq (hka : A 0 ฯ = a) : stepsUntil A a 1 ฯ = 0
Proof
by classical have h_pull : pullCount A a 1 ฯ = 1 := by simp [pullCount_one, hka] have h_le := stepsUntil_pullCount_le (A := A) ฯ a 0 simpa [h_pull] using h_le
Actions: Source ยท Open Issue
Meaning last changed in v4.34.0-rc1-3-g2cf8f3b (2026-08-20).
Self-contained, with its dependencies inlined and proofs replaced by sorry: download the raw file ยท open it in the Lean web editor.
Dependency graph
Audit surface: 2 project declarations, 26 external constants
โ Proved: no sorry anywhere in its closure
This is the tool's own reading of one build's recorded axioms, and it is not robust against an author who wants it to pass. Checking meant to be relied on should go through Comparator, which replays the proof through the kernel from an export against an explicit list of permitted axioms.