Learning.stepsUntil_eq_iff
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stepsUntil_eq_iff🔗
Learning.stepsUntil_eq_iffNo docstring.
Learning.stepsUntil_eq_iff.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] {A : ℕ → Ω → 𝓐} {a : 𝓐} {m : ℕ} {ω : Ω} (n : ℕ) : stepsUntil A a m ω = ↑n ↔ pullCount A a (n + 1) ω = m ∧ ∀ k < n, pullCount A a (k + 1) ω < mLearning.stepsUntil_eq_iff.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] {A : ℕ → Ω → 𝓐} {a : 𝓐} {m : ℕ} {ω : Ω} (n : ℕ) : stepsUntil A a m ω = ↑n ↔ pullCount A a (n + 1) ω = m ∧ ∀ k < n, pullCount A a (k + 1) ω < m
Code
lemma stepsUntil_eq_iff {ω : Ω} (n : ℕ) :
stepsUntil A a m ω = n ↔
pullCount A a (n + 1) ω = m ∧ (∀ k < n, pullCount A a (k + 1) ω < m)Type uses (2)
Body uses (4)
Used by (2)
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Proof
by
refine ⟨fun h ↦ ?_, fun h ↦ ?_⟩
· have h_exists : ∃ s, pullCount A a (s + 1) ω = m := exists_pullCount_eq (by simp [h])
refine ⟨pullCount_add_one_eq_of_stepsUntil_eq_coe h, fun k hk ↦ ?_⟩
exact pullCount_lt_of_le_stepsUntil a ω h_exists (by rw [h]; exact mod_cast hk)
· classical
rw [stepsUntil_eq_dite a m ω, dif_pos ⟨n, h.1⟩]
simp only [Nat.cast_inj]
rw [Nat.find_eq_iff]
exact ⟨h.1, fun k hk ↦ (h.2 k hk).ne⟩Dependency graph
Type dependencies (2)
stepsUntil🔗
Learning.stepsUntil
Number of steps until action a was pulled exactly m times.
Learning.stepsUntil.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (m : ℕ) (ω : Ω) : ℕ∞Learning.stepsUntil.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (m : ℕ) (ω : Ω) : ℕ∞
Code
noncomputable
def stepsUntil (A : ℕ → Ω → 𝓐) (a : 𝓐) (m : ℕ) (ω : Ω) : ℕ∞ :=
sInf ((↑) '' {s | pullCount A a (s + 1) ω = m})Body uses (1)
Used by (46)
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pullCount🔗
Learning.pullCount
Number of times action a was chosen up to time t (excluding t).
Learning.pullCount.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (t : ℕ) (ω : Ω) : ℕLearning.pullCount.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (t : ℕ) (ω : Ω) : ℕ
Code
noncomputable def pullCount (A : ℕ → Ω → 𝓐) (a : 𝓐) (t : ℕ) (ω : Ω) : ℕ := #(filter (fun s ↦ A s ω = a) (range t))
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