Learning.stepsUntil_eq_congr
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stepsUntil_eq_congr🔗
Learning.stepsUntil_eq_congrNo docstring.
Learning.stepsUntil_eq_congr.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] {A : ℕ → Ω → 𝓐} {a : 𝓐} {m n : ℕ} {ω ω' : Ω} (h_eq : ∀ i ≤ n, A i ω = A i ω') : stepsUntil A a m ω = ↑n ↔ stepsUntil A a m ω' = ↑nLearning.stepsUntil_eq_congr.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] {A : ℕ → Ω → 𝓐} {a : 𝓐} {m n : ℕ} {ω ω' : Ω} (h_eq : ∀ i ≤ n, A i ω = A i ω') : stepsUntil A a m ω = ↑n ↔ stepsUntil A a m ω' = ↑n
Code
lemma stepsUntil_eq_congr {ω' : Ω} (h_eq : ∀ i ≤ n, A i ω = A i ω') :
stepsUntil A a m ω = n ↔ stepsUntil A a m ω' = nType uses (1)
Body uses (3)
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Proof
by
simp_rw [stepsUntil_eq_iff n]
congr! 1
· rw [pullCount_congr h_eq]
· congr! 3 with k hk
rw [pullCount_congr]
grindDependency graph
Type dependencies (1)
stepsUntil🔗
Learning.stepsUntil
Number of steps until action a was pulled exactly m times.
Learning.stepsUntil.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (m : ℕ) (ω : Ω) : ℕ∞Learning.stepsUntil.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (m : ℕ) (ω : Ω) : ℕ∞
Code
noncomputable
def stepsUntil (A : ℕ → Ω → 𝓐) (a : 𝓐) (m : ℕ) (ω : Ω) : ℕ∞ :=
sInf ((↑) '' {s | pullCount A a (s + 1) ω = m})Body uses (1)
Used by (46)
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All dependencies, transitively (1)
pullCount🔗
Learning.pullCount
Number of times action a was chosen up to time t (excluding t).
Learning.pullCount.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (t : ℕ) (ω : Ω) : ℕLearning.pullCount.{u_1, u_3} {𝓐 : Type u_1} {Ω : Type u_3} [DecidableEq 𝓐] (A : ℕ → Ω → 𝓐) (a : 𝓐) (t : ℕ) (ω : Ω) : ℕ
Code
noncomputable def pullCount (A : ℕ → Ω → 𝓐) (a : 𝓐) (t : ℕ) (ω : Ω) : ℕ := #(filter (fun s ↦ A s ω = a) (range t))
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