LeanMachineLearning

Learning.Hist.measurable_map๐Ÿ”—

Lemma

No docstring.

Types
  • ๐“ž : Type u_1m๐“ž : MeasurableSpace ๐“žA measurable space is a space equipped with a ฯƒ-algebra.
  • ๐“ž' : Type u_2m๐“ž' : MeasurableSpace ๐“ž'
  • ๐“ : Type u_4m๐“ : MeasurableSpace ๐“
  • ๐“' : Type u_5m๐“' : MeasurableSpace ๐“'
  • ๐“จ : Type u_7m๐“จ : MeasurableSpace ๐“จ
  • ๐“จ' : Type u_8m๐“จ' : MeasurableSpace ๐“จ'
Given
  • fo : ๐“ž โ†’ ๐“ž'
  • fa : ๐“ โ†’ ๐“'
  • fy : ๐“จ โ†’ ๐“จ'
  • n : โ„•
Assuming
  • hfo : Measurable foA function f between measurable spaces is measurable if the preimage of every measurable set is measurable.
  • hfa : Measurable fa
  • hfy : Measurable fy
Then
Measurable (map fo fa fy)
Code
lemma Hist.measurable_map (hfo : Measurable fo) (hfa : Measurable fa) (hfy : Measurable fy)
    (n : โ„•) :
    Measurable (Hist.map fo fa fy (n := n))
Proof
by unfold Hist.map; fun_prop

New in v4.34.0-rc2-74-ge05e4f3 (2026-09-10), and its meaning has not changed since.

Self-contained, with its dependencies inlined and proofs replaced by sorry: download the raw file ยท open it in the Lean web editor.

Dependency graph

Audit surface: 7 project declarations, 10 external constants

โœ“ Proved: no sorry anywhere in its closure

This is the tool's own reading of one build's recorded axioms, and it is not robust against an author who wants it to pass. Checking meant to be relied on should go through Comparator, which replays the proof through the kernel from an export against an explicit list of permitted axioms.