LeanMachineLearning

AEMeasurable.hasLaw_map🔗

Lemma

No docstring.

Types
  • Ω : Type u_1mΩ : MeasurableSpace ΩA measurable space is a space equipped with a σ-algebra.
  • 𝓧 : Type u_2m𝓧 : MeasurableSpace 𝓧
Given
  • P : MeasureTheory.Measure ΩA measure is defined to be an outer measure that is countably additive on measurable sets, with the additional assumption that the outer measure is the canonical extension of the restricted measure.
  • X : Ω → 𝓧
Assuming
  • hX : AEMeasurable X PA function is almost everywhere measurable if it coincides almost everywhere with a measurable function.
Then
ProbabilityTheory.HasLaw X (MeasureTheory.Measure.map X P) P
The predicate HasLaw X μ P registers the fact that the random variable X has law μ under the measure P, in other words that P.map X = μ.
Code
lemma _root_.AEMeasurable.hasLaw_map {X : Ω → 𝓧} (hX : AEMeasurable X P) :
    HasLaw X (P.map X) P
Proof
⟨hX, rfl⟩

Meaning last changed in v4.34.0-rc2-76-g565f652 (2026-09-10).

Self-contained, with its dependencies inlined and proofs replaced by sorry: download the raw file · open it in the Lean web editor.

Dependency graph

Nothing to draw. Its statement rests on no other declaration in this project, and names nothing from a package left unaudited — so the graph is this declaration alone. That is the answer, not a missing picture.

Audit surface: 0 project declarations, 5 external constants

✓ Proved: no sorry anywhere in its closure

This is the tool's own reading of one build's recorded axioms, and it is not robust against an author who wants it to pass. Checking meant to be relied on should go through Comparator, which replays the proof through the kernel from an export against an explicit list of permitted axioms.