LeanMachineLearning

measurable_sigma_of_measurable_comp_mk🔗

Lemma

From the authors

A function on a sigma type is measurable if all its restrictions to the fibers are.

Types
  • α : Type u_1
  • γ : Type u_2MeasurableSpace γA measurable space is a space equipped with a σ-algebra.
Given
  • β : α → Type u_3(a : α) → MeasurableSpace (β a)
  • f : (a : α) × β a → γ
Assuming
  • h : ∀ (a : α), Measurable (fSigma.mk a)A function f between measurable spaces is measurable if the preimage of every measurable set is measurable.
Then
Measurable f
Code
lemma measurable_sigma_of_measurable_comp_mk {f : (Σ a, β a) → γ}
    (h : ∀ a, Measurable (f ∘ Sigma.mk a)) : Measurable f
Proof
fun _ hs ↦ measurableSet_iInf.2 fun a ↦ (h a) hs

New in v4.34.0-rc2-82-ga6c27a7 (2026-09-13), and its meaning has not changed since.

Self-contained, with its dependencies inlined and proofs replaced by sorry: download the raw file · open it in the Lean web editor.

Dependency graph

Nothing to draw. Its statement rests on no other declaration in this project, and names nothing from a package left unaudited — so the graph is this declaration alone. That is the answer, not a missing picture.

Audit surface: 0 project declarations, 6 external constants

✓ Proved: no sorry anywhere in its closure

This is the tool's own reading of one build's recorded axioms, and it is not robust against an author who wants it to pass. Checking meant to be relied on should go through Comparator, which replays the proof through the kernel from an export against an explicit list of permitted axioms.